Bài tập 10 trang 12 sách bài tập (SBT) toán lớp 8 tập 1 cánh diều:Tìm ba số tự nhiên liên tiếp,...

Suppose the three consecutive natural numbers are represented as n, n+1, n+2. Applying the given condition, we get (n+1)*n < (n+2)*(n+1), resulting in n < 12. Hence, we can opt for n = 1,2,3.

Let the three consecutive natural numbers be denoted as x, x+1, x+2. Using the condition given in the question, we can write the inequality as (x+1)*x < (x+2)*(x+1), which simplifies to x < 12. Thus, we can select x = 1,2,3.

Assume that the three consecutive natural numbers are n, n+1, n+2. According to the condition in the question, we have (n+1)*n < (n+2)*(n+1) which leads to n < 12. Hence, we can choose n = 1,2,3.

Let's denote the three consecutive natural numbers as x, x+1, x+2. Given that the product of the second and third numbers is greater than the product of the first and second numbers by 12 units, we have the inequality (x+1)*x < (x+2)*(x+1), which simplifies to x < 12. Therefore, we can choose x = 1,2,3.

Đặt ba số tự nhiên liên tiếp là n, n+1, n+2. Theo điều kiện đề bài ta có: (n+1)n < (n+2)(n+1) <=> n^2 + n < n^2 + 2n + 1 <=> 0 < n + 1 <=> -1 < n. Ta chọn n = 1,2,3.